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Have an upcoming recruitment exam that is based on AMCAT? This study pack will get you ready for your best performance in the test, Fast and Easy! AMCAT Exam in Nigeria is popularly conducted by Jobberman. Next AMCAT Job Aptitude Test is Happening Soon!
This study pack, (AMCAT Aptitude Test Questions and Answers Study pack), will help you prepare faster for all AMCAT based job aptitude tests mostly used in Nigeria by jobberman.
To perform your best, it is very crucial to practice as many questions as you can find. Mostly, using questions which have appeared in previous AMCAT tests since there is a very good chance to find repeated questions in your actual test.
Solving these will also help you understand the exam pattern, know the level of difficulty and ultimately, and help you create your best preparation strategy. Your speed and accuracy in answering the questions is key to your success at the AMCAT.
AMCAT Aptitude Test usually comprise of 3 or 4 paper sections. This includes;
Although there are a lot of AMCAT questions online, you need to figure out which one Jobberman is likely going to use in 2019. So we have put together the most comprehensive AMCAT questions required to prepare you properly for the test.
AMCAT Aptitude Test Questions and Answers Study pack is in .PDF (Ebook) format.
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Quantitaive Reasoning
1.A man is riding a bike with front and back wheel circumference of 40 inches and 70 inches respectively. If the man rides the bike on a straight road without slippage, how many inches will the man have travelled when the front wheel has made 15 revolutions more than the back wheel?
A. 1100
B. 1120
C. 1400
D. 1300
The correct answer is C.
Explanation:
: Given the ratio of the circumference of front wheel is 40 inches and back wheel is 70 inches
Distance covered = Circumference of the wheel × No. of Revolutions made by the wheel
If n is the number of revolutions made by back wheel, the number of revolutions made by front wheel is n+15
Distance covered by both the wheels is the same
40*(n+3)=70n
n=20
Front wheel : Back Wheel
Circumference 40 : 70
Revolutions 35 : 20
Distance covered 40×35 = 70×20 = 1400
(OR)
We know that
Revolution is inversely proportional to the circumference
So revolution will be in ratio 70X : 40X
7X : 4X
Given that front wheel made 15 revolutions more than the back here the difference is 7X-4X=3X
3X=15
Then X=5
Revolution in ratio 7×5:4×5=35:20
Front wheel : Back Wheel
Circumference 40 : 70
Revolutions 35 : 20
Distance covered 40×35 = 70×20 = 1400
2.In a palace, three different types of coins are there namely gold, silver and bronze. The number of gold, silver and bronze coins is 18000, 9600 and 3600 respectively. Find the minimum number of rooms required if in each room should give the same number of coins of the same type.
A. 12
B. 18
C. 32
D. 24
E. 26
The correct answer is D.
Explanation:
Gold coins=18000 Silver coins=9600 Bronze coins=3600
Find a number which exactly divide all these numbers
That is HCF of 18000, 9600& 3600
All the value has 00 at end so the factor will also have 00 find HCF for180, 96 &36
Factors of
180=22×32×5
96=25×3
36=32×22
Common factors are 22×3=12
Actual HCF is 1200
Gold coins (18000/1200) will be in 15 rooms
Silver coins (9600/1200) will be in 8 rooms
Bronze coins (3600/1200) will be in 3 rooms
Total rooms will be (15+8+3) = 26 rooms
3. Find the two-digit numbers A and B such that the number 65AB0 is divisible by 66.
A. 15, 16
B. 16, 16
C. 17, 17
D. 17, 18
The correct answer is C.
Explanation:
Given no 65AB0 have to be divided by 66
Co primes of 66 are 6 &11
The no have to divided by 6 and by 11
Divisibility check for 11
Option 15,16
+ 6 – 5 + 1 – 5 + 1 – 6 + 0 = – 8 (not divisible by 11)
Option 16,16
+ 6 – 5 + 1 – 6 +1 – 6 + 0 = – 9(not divisible by 11)
Option 17,17
+ 6 – 5 + 1 – 7 + 1 – 7 + 0 = -11(divisible by 11)
Option 17, 18
+ 6 – 5+ 1– 7 + 1 – 8 +0 = – 12(not divisible by 11)
Checking the answer with divisibility of 6
Divisibility rule for 6 is that it has to be divisible by 2 & by 3
The No. is Even No. so it is divisible by 2
6+5+1+7+1+7+0=27(it is also divisible by 3)
So A=17,B=17
4. Find the number of factors of 9600.
A. 46
B. 48
C. 42
D. 50
The correct answer is B.
Explanation:
9600=27×31×52
Total no. of factors = (7+1)(1+1)(2+1)
= 8×2×3
=48
5.Find the unit digit of 4198 + 612345 + 34866 + 2411 + 1.
A. 0
B. 1
C. 2
D. 3
The correct answer is B.
Explanation:
Unit digit of 4198 + 612345 + 34866 + 2411 + 1
Power cycle of
4 is 4,6
6 is 6
8 is 8,4,2,6
1 is 1
4198 198 is even number the unit digit value is 6
612345 it is always + 6
34866 66/4 the remainder is 2 the second value is+ 4
2411 11 is odd number the unit digit value is + 4
1 it is always + 1
Total = 21
LOGICAL Reasoning
Directions for questions: There are six persons P, Q, R, S, T and U. R is the sister of U, Q is the brother of T’s Husband, S is the father of P and Grandfather of U. There are two fathers, three brothers and a mother in the group.
1.Who is the mother?
A. T
B. S
C. Q
D. R
The correct answer is A.
2. How many male members are there in the group?
A. 1
B. 2
C. 3
D. None of these
E. cannot be determined
The correct answer is D.
3. How is U related to T?
A. Uncle
B. Son
C. Husband
D. Data insufficient
The correct answer is D.
Directions for questions: The managing director of a company appoints planning committees, each consisting of exactly three members. The persons eligible for appointment are three executives from Finance – F, G and H – and three executives from Operations – K, L and M. Any given committee is subjected to the following restrictions on appointments:
a. At least one member must be from Finance and at least one member must be from Operations.
b. If F is appointed, G cannot be appointed.
c. Neither H nor L can be appointed unless the other is also appointed.
d. If K is appointed, M must also be appointed.
4.Which of the following is an acceptable committee?
A. K, M, F
B. F, G, K
C. H, F, G
D. Data Inadequate
The correct answer is A.
5. If appointees from Finance are in majority in a certain committee, that committee must include
A. F
B. L
C. K
D. G
The correct answer is B.
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